X^2+30x-5=0

Solution for X^2+30x-5=0 equation:

X^2+30X-5=0

a = 1; b = 30; c = -5;
Δ = b2-4ac
Δ = 302-4·1·(-5)
Δ = 920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{920}=\sqrt{4*230}=\sqrt{4}*\sqrt{230}=2\sqrt{230}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{230}}{2*1}=\frac{-30-2\sqrt{230}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{230}}{2*1}=\frac{-30+2\sqrt{230}}{2}
$